Java Program to Find the Perimeter of a Rectangle
A Rectangle is a polygon with four sides where all the internal angles are equal to 90°. In the rectangle, only the opposite sides are equal in length, unlike the square, where all the sides are equal. Suppose one side of the rectangle is 15 cm; its opposite side will also be 15 cm. In the below image, the sides A and C and B and D are equal.
The perimeter of a rectangle is defined as the addition of all its sides. Thus, its perimeter can be calculated using the formula below.
Perimeter = A + B + C + D
Since the opposite sides of a rectangle are equal, its perimeter can also be calculated as given below.
Perimeter = A + B + C + D = A + B + A + B = 2A + 2B = 2(A+B)
Example----
Input
A = 10, B = 5, C = 10, D = 5.
Output
The perimeter of the rectangle is 30
Explanation
2(A + B) = 2(10 + 5) = 30.
Implementation
Please go through the example below, where we have implemented a Java program to calculate the perimeter of a rectangle.
FileName: RectPerimeter.java
// Java program to calculate the perimeter of a rectangle
import java.util.*;
public class RectPerimeter {
// main method
public static void main(String[] args) {
int a, b, c, d;
int perimeter;
a = c = 10;
b = d = 5;
perimeter = a + b + c + d;
// Another formula
//perimeter = 2 * (a + b);
// Display the perimeter
System.out.println("The perimeter of the given rectangle is " +perimeter);
}
}
Output:
The perimeter of the given rectangle is 30