numpy.tile() in Python
The numpy.tile() function constructs an array by repeating the parameter ‘A’ the number of times as specified by the ‘reps’ parameter.
Syntax
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numpy.tile(A, reps) |
Parameter
The numpy.tile() function consists of two parameters, which are as follows:
A: This parameter represents the input array.
reps: This parameter represents the number of repetitions of A along each axis.
Return
This function returns the tiled output array.
Example 1
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# Python Program explaining # numpy.tile() function import numpy as np #Working on 1D A = np.arange(4) print("arr value: \n", A) rep = 3 print("Repeating A 3 times: \n", np.tile(A, rep)) rep = 5 print("\nRepeating A 5 times: \n", np.tile(A, rep)) |
Output
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arr value: [0 1 2 3] Repeating A 3 times: [0 1 2 3 0 1 2 3 0 1 2 3] Repeating A 5 times: [0 1 2 3 0 1 2 3 0 1 2 3 0 1 2 3 0 1 2 3] |
Example 2
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# Python Program explaining # numpy.tile() function import numpy as np arr = np.arange(4).reshape(2, 2) print("arr value: \n", arr) val1 = 2 val2 = 1 rep = (val1, val2) print("\nRepeating arr: \n", np.tile(arr, rep)) print("arr Shape : \n", np.tile(arr, rep).shape) val1 = 2 val2 = 3 rep = (val1, val2) print("\nRepeating arr : \n", np.tile(arr, rep)) print("arr Shape : \n", np.tile(arr, rep).shape) |
Output
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arr value: [[0 1] [2 3]] Repeating arr : [[0 1] [2 3] [0 1] [2 3]] arr Shape : (4, 2) Repeating arr : [[0 1 0 1 0 1] [2 3 2 3 2 3] [0 1 0 1 0 1] [2 3 2 3 2 3]] arr Shape : (4, 6) |