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Fee Management System in C

The concept is to split every operation into its very own characteristic. Software is made from all of the capabilities mixed with transfer cases. An example of the capabilities may be observed below:

1. execute():

This characteristic will use Switch Statements to perform the subsequent capability and show the software's to be had options.

Functionality: Show Eligible Students Add Student Details Delete Student Record Update Eligibility Criteria Print Student Details.

2. add():

This characteristic receives facts from the person and updates the college students' listing. Verify that the student’s Roll Number is precise earlier than including the student to the listing. The college students to be added specifics are as follows:

Name of the student, the roll number, the fame of the fees, and the attendance report of eligible.

3. Students():

This characteristic receives facts from the person, updates the eligibility for the exams, and presentations the specified percent of preceding attendance for exams. By iterating over the listing of student records, it additionally updates the price fame required for examination eligibility. For every student, it assessments to peer if their attendance percent exceeds the specified percent and updates the price fame.

4. print_student():

The info of every student is revealed after this characteristic iterates thru the listing of college students.

5. delete():

To delete a student report and replace the student’s listing, this characteristic obtains the roll number.

// Function that adds the student's
// record in Examination Management
// Project
void add(struct student s[50])  {
printf("Enter the total ");
printf("number of working days \n");
scanf("%f", &tdays);
printf("Enter the number of students \n");
scanf("%d", &n);
    for (i = 0; i< n; i++) {
printf("Student number %d \n",(i + 1));
printf("Enter the name of  the student \n");
scanf("%s", s[i].name);
printf("Enter the roll number \n");
scanf(" %d", &s[i].rno);
printf("Enter the fees of the student 'P' for paid 'N' for not paid \n");
scanf(" %c", &s[i].fees);
printf("Enter the number of days the student was  present \n");
scanf("%f", &s[i].days);
        s[i].attend = (s[i].days / tdays)* 100;
printf("student attendance" " = %f \n",s[i].attend);
    }
execute();
}
// C program for the Examination
// Management System
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int option = 0;
int i = 0;
int n = 0;
int j = 0;
float present = 75.00;
char money = 'P';
float tdays = 1;
// Structure of Student
struct student {
    char name[20];
    int rno;
    char fees;
    float days;
    float attend;
} s[50];
// Functions
void add(struct student s[]);
void eligibleStudents(struct student s[]);
void execute();
void printStudents(struct student s[]);
void deleteRecord(struct student s[]);
// Function to execute the software
// for the student examination
// registration system
void execute()
{
printf(“ Enter the serial number  to select the option \n");
printf(" 1. To show Eligible candidates \n");
printf(" 2. To delete the student record \n");
printf(" 3. To change the eligibility criteria \n");
printf(" 4. Reset the eligibility criteria \n");
printf(" 5. Print the list of all the student \n");
printf(" Enter 0 to exit \n");
scanf("%d", &option);
// Switch Statement for choosing
    // the desired option for the user
    switch (option) {
    case 1:
eligibleStudents(s);
execute();
        break;
    case 2:
deleteRecord(s);
execute();
        break;
    case 3:
printf("Old Attendance required = %f",present);
printf( "\n Enter the updated attendence required \n");
scanf("%f", &present);
printf("fees status required  was %c \n",money);
printf("Enter the new fees "
               "status 'P' for paid 'N' "
               "for not paid and "
               "'B' for both \n");
scanf("%c", &money);
printf("Eligibility Criteria updated \n");
execute();
        break;
    case 4:
        present = 75.00;
        money = 'P';
printf("Eligibility creitria reset \n");
execute();
        break;
    case 5:
printStudents(s);
execute();
        break;
    case 6:
execute();
        break;
    case 0:
exit(0);
    default:
printf("Enter number only from 0-4 \n");
execute();
    }
}
// Function to print the students record
void printStudents(struct student s[])
{
    // Loop to iterate over the students
    // students records
    for (i = 0; i< n; i++) {
printf("Name of student %s \n",s[i].name);
printf("Student roll number = %d \n",s[i].rno);
printf("Student fees status = %c \n",s[i].fees);
printf("Student number of days present = %f \n",s[i].days);
printf("Student attendence = %f \n",
               s[i].attend);
    }  }
// Function to Student Record
void deleteRecord(struct student s[])  {
    int a = 0;
printf("Enter the roll number of the student to delete it ");
scanf("%d", &a);
    // Loop to iterate over the students
    // records to delete the Data
    for (i = 0; i<= n; i++) {
        // Condition to check the current
        // student roll number is same as
        // the user input roll number
        if (s[i].rno == (a)) {
// Update record at ith index
            // with (i + 1)th index
for (j = i; j < n; j++) {
strcpy(s[j].name, s[j + 1].name);
                s[j].rno = s[j + 1].rno;
                s[j].fees = s[j + 1].fees;
                s[j].days = s[j + 1].days;
                s[j].attend = s[j + 1].attend;
            }
printf("Student Record deleted");
        }
    }
}
// Function to print the student
// details of the eligible students
void eligibleStudents(struct student s[])
{
printf("____________________________________________________ \n");
printf("Qualified student are = \n");
// Iterate over the list
    // of the students records
    for (i = 0; i< n; i++) {
        // Check for the eligibility
        // of the student
        if (s[i].fees == money || 'B' == money) {
            if (s[i].attend>= present) {
printf("Student name = %s \n",s[i].name);
printf("Student roll no. = %d \n",s[i].rno);
printf(" Student fees = %c \n",s[i].fees);
printf(" Student attendence = %f \n",s[i].attend);
            }
        }
    }
}
// Function to add the students record
void add(struct student s[50])
{
printf("Enter the total ");
printf("number of working days \n");
scanf("%f", &tdays);
printf("Enter the number");
printf("of students \n");
scanf("%d", &n);
    for (i = 0; i< n; i++) {
printf("Student number %d \n",
               (i + 1));
printf("Enter the name ofthe student \n");
scanf("%s", s[i].name);
printf("Enter the roll number \n");
scanf(" %d", &s[i].rno);
printf("Enter the fees of thestudent 'P' for paid, 'N' for not paid \n");
scanf(" %c", &s[i].fees);
printf("Enter the number ofdays the student was present \n");
scanf("%f", &s[i].days);
        s[i].attend = (s[i].daystdays) * 100;
printf("student attendence = %f \n", s[i].attend);
    }
execute();
}
 // Driver Code
int main()
{
printf("Welcome to Student database registration \n");
printf("Enter 0 to exit \n");
printf("Enter 1 to add student record \n");
scanf("%d", &option);
    // Switch Statements
    switch (option) {
    case 0:
exit(0);
    case 1:
        add(s);
        break;
     default:
printf("Only enter 0 or 1");
execute();   }
    return 0;
}

Output:

Welcome to student database registration
Enter 0 to exit
Enter 1 to add student record
1
Enter the total number of working days
50
Enter the number of students
2
Student number 1
Enter the name of the student
Rudra
Enter the roll number
1
Enter the fees of the student ‘p’ for paid , ‘n’ for not paid
P
Enter the number of days the student was present
40
Student attendance = 80.000000
Student number 2
Enter the name of the student
Rudra1
Enter the roll number
2
Enter the fees of the student ‘p’ for paid , ‘n’ for not paid
n
Enter the number of days the student was present
45
Student attendance = 90.000000