Scope Resolution Operator in C++
The scope resolution operator and its different usage in the C++ programming language will be discussed in this section. The scope resolution operator is used to refer to an out-of-scope global variable or member function. As a result, we employ the scope resolution operator to access a program's hidden variable or function. The double colon ( :: ) sign represents the operator.
If a global and local variable or function in a system with the same name, and we call it a variable, only the internal or local variables are automatically accessed, without access to the global variable. Hides global flexibility or function in this way. To circumvent this, we use a scope resolution operator to detect hidden variables or function in the system. You can use a wide range of operator to announce the work within the classroom and define it outside the classroom later. In the example below, we announce how Speed in a Bicycle class. Later, we will use a wide range of operator to define the function in the main section.
If you have a local variable with the same name as the global variable, you can use the scope resolution operator to access it. We have two variables, both named num, with global and local scope in the example below. As a result, you must use the scope resolution operator to access the global num variable in the main class.
The scope resolution operator is used in a variety of ways:
- It's utilized to get at a program's hidden variables or member functions.
- It uses scope resolution to define the member function outside of the class.
- It's used to get reach a class's static variables and static functions.
- Inheritance uses the scope resolution operator to override functions.
Using the scope resolution ( :: ) operator, create a program to access the concealed value.
Let us look at an example of a program using scope resolution operator:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
using namespace std ;
// declare global variable
int number = 40 ;
int main ( )
{
// declare local variable
int number = 60 ;
// print the value of the variables
cout << " The value of the local variable number: " << number ;
// use scope resolution operator ( :: ) to access the global variable
cout << "\n The value of the global variable number: " << :: number ;
return 0 ;
}
OUTPUT:
The value of the local variable number: 40
The value of the global variable number: 60
…………………………………………………………………
Process executed in 2.22 seconds
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Example:
In the above example of a program in C++, we have demonstrated the use of scope resolution, here we are declaring a global variable number and in the main function we are trying to access it with the help of scope resolution operator.
Using the scope resolution ( :: ) operator, specify the member function outside of the class.
Let us look at an example of a program to specify the member function outside of the class:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
using namespace std ;
class Operate
{
public:
// declaration of the member function
void fun ( ) ;
};
// define the member function outside the class.
void Operate :: fun ( ) /* return_type Class_Name :: function_name */
{
cout << " It is the member function of the class. " ;
}
int main ( )
{
// create an object of the class Operate
Operate op ;
op.fun ( ) ;
return 0 ;
}
OUTPUT:
It is the member function of the class.
……………………………………………………….
Process executed in 0.11 seconds
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Explanation:
In the above example of a program in C++, we have demonstrated how we can access the member function of a class by using scope resolution operator. Here we are making void function and adding scope resolution operator to access the fun member function of the above class Operator.
Using the scope resolution ( :: ) operator, illustrate the standard namespace.
Let us look at an example of a program using scope resolution operator to demonstrate the standard namespace:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
int main ( )
{
int num = 0 ;
// use scope resolution operator with std namespace
std :: cout << " enter the value of num: " ;
std :: cin >> num ;
std :: cout << " The value of num is: " << num ;
}
OUTPUT:
enter the value of num: 50
The value of num is: 50
……………………………………...
Process executed in 2.11 seconds
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Explanation:
In the above example of a program in C++, we have demonstrated how scope resolution can illustrate standard namespace. Here as you can notice we have not used using namespace std so scope resolution can illustrate standard namespace by adding std ( :: ).
Using the scope resolution ( :: ) operator, access the static variable.
Let us look at an example of a program using scope resolution operator which accesses the static variables in C++:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
using namespace std ;
class Parent
{
static int n1 ;
public:
static int n2 ;
// The class member can be accessed using the scope resolution operator.
void fun1 ( int n1 )
{
// n1 is accessed by the scope resolution operator ( :: )
cout << " The value of the static integer n1: " << Parent :: n1 ;
cout << " \n The value of the local variable n1: " << n1 ;
}
} ;
// define a static member explicitly using :: operator
int Parent :: n1 = 5 ; // declare the value of the variable n1
int Parent :: n2 = 10 ;
int main ( )
{
Parent b ;
int n1 = 15 ;
b.fun1 ( n1 ) ;
cout << " \n The value of the Base :: n2 = " << Parent :: n2 ;
return 0 ;
}
OUTPUT:
The value of the static integer n1: 5
The value of the local variable n1: 15
The value of the Base :: n2 = 10
……………………………………………………
Process executed in 2.22 seconds
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Explanation
In the above example of a program in C++, we have demonstrated how scope resolution operator can access static variables. Here in the parent class we have declared static variable of integer type, later we made a void fun function where scope resolution operator after the class name is trying to access the static variables.
Using the scope resolution ( :: ) operator, access the static member function.
Let us look at an example of a program using scope resolution operator which accesses the static member function:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
using namespace std ;
class ABC
{
public:
// declare static member function
static int fun ( )
{
cout << " \n Use scope resolution operator to access the static member. " ;
}
} ;
int main ( )
{
// class_name :: function name
ABC :: fun ( ) ;
return 0 ;
}
OUTPUT:
Use scope resolution operator to access the static member.
………………………………………………………………………………………
Process executed in 1.13 seconds
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Explanation
In the above example of a program in C++, we have demonstrated how scope resolution operators can access static member function. Here as you can observe the function names fun is statically declared and we want class ABC to access is, so with the help of scope resolution after the class name and then function name we can access the static member function.
Using the scope resolution ( :: ) operator, override the member function.
Let us look at an example of a program using the scope resolution operator which overrides the member function:
#include < iostream >
#include < bits/stdc++.h >
#include < stdio >
#include < stdlib >
using namespace std ;
class ABC
{
// declare access specifier
public:
void test ( )
{
cout << " \n It is the test ( ) function of the ABC class. " ;
}
} ;
// derive the functionality or member function of the base class here
class child : public ABC
{
public:
void test ( )
{
ABC :: test ( ) ;
cout << " \n It is the test ( ) function of the child class. " ;
}
} ;
int main ( )
{
// create object of the derived class
child ch ;
ch.test ( ) ;
return 0 ;
}
OUTPUT
It is the test ( ) function of the ABC class.
It is the test ( ) function of the child class.
……………………………………………………………..
Process executed in 2.22 seconds
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Explanation:
In the above example of a program in C++, we have demonstrated how scope resolution operator can override the member function. Here the concept inheritance comes in action. We have created a derived class child using the base class ABC so we have performed single inheritance and in the derived class we have made a void function called test, and using scope resolution operator we are trying to access test function by class ABC.