C++ Continue in Do-while loop
Continue statement:
Inside the loop, the continue statement is used to control the loop.
C++ utilizes the continue keyword to implement the continue statement, which transfers the program's flow at the start of the loop and skips the current statement when it is reached. Continue statement is used in all the iteration control loops.
Syntax:
The syntax of the continue statement is:
continue;
- Continue is a predefined keyword.
- The continue statement can’t be used outside of the iteration loop. It only appears in iteration statements.
Flowchart:
Explanation:
The statements within the loop are executed based on the loop condition. If the specified condition is true, the loop iteration will be continued to execute and the loop is terminated when the specified condition is false. The continue statement skips the current statement and passes control to the next loop iteration when the continue keyword is used inside a loop.
What is Do-While Loop?
An iterative loop that checks the condition at the end.
The Do-While loop can be used whenever a test condition is specific, as the control enters the loop at a minimum once before the condition is evaluated. This loop checks the given condition after the execution of looping statements.
The loop actions or statements will be repeated infinitely as long as the test requirements are met.
Note: DO-WHILE LOOP means “first do it, then check”.
Syntax:
The Syntax of the DO-WHILE loop is:
Do
{
statement(s);
}
while(expression);Continue in Do-While loop
The continue statement breaks one iteration (in the loop) if a specified condition occurs, and continues with the next iteration in the loop.
Syntax:
do ( ){
{
// ...
continue;
updation;
}
} while( ,) Examples of Continue in Do-While loop
Algorithm to print the list of numbers:
Step 1: Start the program.
Step 2: Read n and i.
Step 3: Initialise i=1.
Step 4: Print the value of I,
If (i==3)
Continue;
Else
go to step 5.
Step 5: Iterate until I<=10 if the condition is false then go to step 4.
Step 6: Stop.
Program:
#include<iostream>
using namespace std;
int main()
{
int i, n;
cout << "Enter a number";
cin >> n;
cout << "the list of numbers are";
do(i=1)
{
i++;
if(i == 5)
{
continue;
}
cout << i;
}while(i<=n)
return 0;
}The output of the program:
Enter a number: 10
The numbers are:
1
2
3
4
6
7
8
9
10
Explanation:
The program is designed to print the list of numbers which are entered by the user.
We have used the do while loop method in the above code to demonstrate the implementation of the continue statement.
We've set up two variables: "n" for entering the value and "i" for the iteration. The program asks the user for a number, which is then stored in variable ‘n’. We initialized i to 0(i=0). And, we used the continue statement inside the loop to skip number five. If the number is not 5, the statement outside the ‘if condition’ is executed, and the number is printed one by one.
After that, we use a condition as text expression that verifies the value of "i" is less than or equal to n (i<=n).
Algorithm to print Odd numbers using continue statement:
Step 1: Start the program.
Step 2: Read n and i.
Step 3: Initialise i=1.
Step 4: Iterate until i<=10 if the condition is false then go to step 6.
Step 5: Print the value of I.
If (i%2==0)
Continue;
Else
go to step 4.
Step 6: exit
Program:
#include<iostream>
using namespace std;
int main()
{
int i, n;
cout << "Enter a number";
cin >> n;
cout << "Odd numbers";
do(i=1)
{
i++;
if(i%2==0)
{
continue;
}
cout<<i;
} while(i<=n)
return 0;
}
Output:
The output of the program
Enter a number: 10
Odd numbers:
1
3
5
7
9Explanation:
We have used the do while loop method in the above code to demonstrate the implementation of the continue statement.
We've set up two variables: "n" for entering the value and "i" for the iteration. The program asks the user for a number, which is then stored in variable ‘n’. We initialized i to 1(i=1).
After then, we used the continue statement inside the loop to skip the even numbers with the logic (i%2==0). if the condition is true according to the logic then the number is skipped. And, if the number is not even, the statement outside if condition is executed, and the odd numbers are printed one by one.
After that, we use a condition as text expression that verifies the value of "i" is less than or equal to n (i<=n).
Continue with the Nested loop:
When the continue keyword is used with nested loops, the current iteration of the inner loop is skipped.
Program:
#include <iostream>
using namespace std;
int main()
{
int n;
int sum=0;
do(i=1)
{
I++;
do(i=1)
{
j++;
if (j ==3)
{
continue;
}
cout << "i = " << i << ", j = " << j << endl;
} while(j<=5)
}while(i<=5)
return 0;
}Output:
i = 1, j = 2
i = 1, j = 4
i = 1, j = 5
i = 2, j = 2
i = 2, j = 4
i = 2, j = 5
i = 3, j = 2
i = 3, j = 4
i = 3, j = 5
i = 4, j = 2
i = 4, j = 4
i = 4, j = 5
Explanation:
When the continue statement is used in the above program, it skips the current iteration of the inner loop. And the program's control shifts to the update expression of inner loop. As a result, the value of j=3 never appears in the output.