Print Table Using Do while Loop in C++

Multiplication Table

In mathematics, a table is created by multiplying a certain number by all of the counting numbers, i.e., 1, 2, 3, 4, 5, 6, and so on. It is also referred to as a multiplication table. Suppose, we need to create a table of the number 7, then we have to multiply 7 by each natural number as follows:

7 * 1 = 7
7 * 2 = 14
7 * 3 = 21
7 * 4 = 28
7 * 5 = 35

What is Do-While Loop?

An iterative loop that checks the condition at the end.
The Do-While loop can be used whenever a test condition is specific, as the control enters the loop at a minimum once before the condition is evaluated. This loop checks the given condition after the execution of looping statements.

The loop actions or statements will be repeated infinitely as long as the test requirements are met.

Note: DO-WHILE LOOP means “first do it, then check”.

Syntax:

The Syntax of the DO-WHILE loop is:

Do
           { 
            statement(s);
           } 
         while(expression);

Program to print multiplication of 2 tables from (1 to 12)

Algorithm

Step 1: Start

Step 2: Read n, res, I;

Step 3: Take a number “n” from the user to print the table

Step 4: Use Do While loop to print table. Initialize (i=1) and check condition until i becomes 12. when, the condition becomes wrong, then control moves to step 6.

Step 5: res=num*i;

Step 6: Print “res”.

Step 7: End.

Program

#include<iostream>
using namespace std;
int main()
{
    int num=2, i, res;
   i=1; 
do{
        res = num*i;
        cout<<num<<" * "<<i<<" = "<<res;
        cout<<endl;
i++;
    }while(i<12);
    cout<<endl;
    return 0;
}

Output

2 * 1 = 2
2 * 2 = 4
2 * 3 = 6
2 * 4 = 8
2 * 5 = 10
2 * 6 = 12
2 * 7 = 14 
2 * 8 = 16
2 * 9 = 18
2 * 10 = 20
2 * 11 = 22
2 * 12 = 24

Explanation

The above code prints the table of 2.
The do while loop is used in this program. And, the control enter in the loop and execute the operation and stores the value of num*i, i.e., 2*1, i.e., 2.

Then, the following statement will exexute:
cout<<num<<" * "<<i<<" = "<<res;

The above statement prints the first line like this 2 *1 = 2 in the output. In the loop, (cout<<endl) is next statement that indicates the program will write the output from new line.

Initially, value of i is initialized to 1, and the update statement which increases the value of i. After that, the condition checks and evaluates to true because (2<12), which allows the program to enter in loop again.
This process will continue until the condition is determined to be untrue.
The multiplication table of 2 is printed on the output screen.

Program to print a table of any user-defined number

#include<iostream>
using namespace std;
int main()
{
    int num, i, res;
    cout<<"Enter the Number: ";
    cin>>num;
    i=1;
    do{
        res = num*i;
        cout<<num<<" * "<<i<<" = "<<res;
        cout<<endl;
    i++;
} while(i<=10);
    cout<<endl;
    return 0;
}

Output

Enter a number: 10
10 * 1 = 10
10 * 2 = 20
10 * 3 = 30
10 * 4 = 40
10 * 5 = 50
10 * 6 = 60 
10 * 7 = 70
10 * 8 = 80
10 * 9 = 90
10 * 10 = 100

Program to print table from 1 to 10

Algorithm

Step 1: Start the program.

Step 2: Read n, i=1, j=1.

Step 3: Use two do-while loops to print the tables

               Iterate the value of i until i=10

                  à in the inner loop itearate j until (j<=n) else go to step4

 Step 4: If (j<n-1)

                 Cout<<j<<”x”<<i<<i*j

               Else

                 Cout<<j<<”x”<<i<<i*j

Step 5: End the program.

Flowchart:

Program

#include <iostream>
using namespace std;
int main()
{
    int j, i, n;
   cout << "\n\n the multipliaction table from 1 to n:\n";
    cout << "-------------------------------------------------------------\n";
    cout << "Input the number upto 5: ";
    cin >> n;
    cout << "Multiplication table from 1 to " << n << endl;
    i=1;
   do {
        j=1;
        do{
            if (j<=n-1)
                cout<<j<<"x"<<i<<"="<<i*j<<"\t";
            else
                cout<<j<<"x"<<i<< "=" <<i*j<<endl;
        j++;
    }while(j<=n);
i++;
}while(i<=10);
        cout << endl;
     }

Output

Enter any number: 
The multiplication table from 1 to 4
1x1=1    2x1=2      3x1=3         4x1=4  
1x2=2    2x2=4      3x2=6         4x2=8  
1x3=3    2x3=6      3x3=9         4x3=12  
1x4=4    2x4=8      3x4=12        4x4=16                                  
1x5=5    2x5=10    3x5=15         4x5=20                                
1x6=6    2x6=12   3x6=18          4x6=24                                
1x7=7    2x7=14   3x7=21          4x7=28                                  
1x8=8    2x8=16   3x8=24          4x8=32                                
1x9=9    2x9=18   3x9=27          4x9=36                              
1x10=10  2x10=20  3x10=30         4x10=40  

Program to print table using recursive:

#include <iostream>
using namespace std;
 void mul_table(int N, int i)
{
    // Base Case
    if (i > 10)
        return;
       cout << N << " * " << i << " = " << N * i << endl;
      return mul_table(N, i + 1);
}
 
// Driver Code
int main()
{
    int N = 7;
    mul_table(N, 1);
    return 0;
}

Output:

7 * 1 = 7
7 * 2 = 14
7 * 3 = 21
7 * 4 = 28
7 * 5 = 35
7 * 6 = 42
7 * 7 = 48
7 * 8 = 56
7 * 9 = 63
7 * 10 = 70