Python Strong Number
Strong Number- Logic
- Divide each of the number's digits into separate units to determine if it is a strong number or not.
- The factorial of each digit must then be determined. The values produced for each digit following the factorial operation will then be added.
- In the end, the sum needs to be compared to the supplied number. The number is a strong one if the response is yes.
Algorithm
To determine whether a given number is a strong number or not, apply the algorithm provided below.
- Obtain the required number and use it as input to determine if it is a strong number or not. Let's assign this input number to the variable N.
- Put N's value in a short-term variable called temp_N.
- Put a variable's value, such as "sum," to zero. This will record the factorial sum for every digit of N.
- The last digit of the number needs to be preserved in a variable, such as the last digit = N % 10.
- It is necessary to keep the factorial of the last digit in a variable called fact.
- Every time the factorial of the last digit is found, the sum should be raised.
sum = sum + fact - The number must be divided by 10 to become smaller in units after each factorial operation.
N=N/10 - Until N > 0, then repeat steps 4 through 7.
- When the loop is finished, the condition sum = temp N should be tested to see if the sum equals the number. If the answer is affirmative, the input number is a strong one.
Strong Number Program Implementation in Python
The algorithm described above is used to build the following Python computer code, which enables us to detect whether a given integer is a strong number or not.
Strong Number with while Loop in Python
Example 1:
sum = 0
N = int(input("Enter a number: "))
temp_N = N
while(N):
k = 1
fact = 1
r = N % 10
while(k <= r):
fact = fact * k
k = k + 1
sum = sum + fact
N = N//10
if(sum == temp_N):
print(str(temp_N) + " is a strong number")
else:
print(str(temp_N) + " is not a strong number")
Output:

- The user is initially prompted for input when the program is run. We can pass the necessary number to determine if it is a strong number or not. In this instance, we entered after passing 145.
- The response is "145 is a strong number," which is the appropriate output. This is demonstrated in the screenshot above.
- Passing another input now. Once more, we exceeded 163. Since 163 is a weak number, we obtained the results depicted below.

The software code that we just looked at conducts a simple number check. We might occasionally need to confirm this for several numbers at once.
Finding Strong Numbers in a List Using a Python Program
We'll employ another Python method for this. We can do this with the aid of the Python program code listed below. Examine the Python programming code that follows carefully to observe how each component carries out its intended function.
Example 2:
# Compute factorial
def factorial1(N):
if(N == 0 or N == 1):
fact = 1
else:
fact = N * factorial1(N - 1)
return fact
# Check for strong number
def strong_number(list):
n_list =[]
for i in list:
temp_N = i
sum = 0
while(temp_N):
r = temp_N % 10
sum += factorial1(r)
temp_N = temp_N // 10
if(sum == i):
n_list.append(i)
else:
pass
return n_list
# Input
a = [10, 25, 2, 121, 145, 786, 49, 1, 20900]
strong_num_list = strong_number(a)
print(strong_num_list)
Output:

- The Python program code presented above is divided into three sections. Firstly the fact N() function, which determines the factorial of the parameterized number. Second, there is the strong number() function, which adds up each digit's factorial sum in the given number.
- The strong_number() function accepts a list as a parameter since we want to list several numbers as input. The strong_number function first creates a bare list called n list.
- A while loop computes the factorial total for each digit. The method then returns the value if the sum does equal the supplied number.
- The input portion is the third component of the program. Simply giving the necessary values and running the application will allow us to pass them.
- The list is given to the strong number function, which returns one or more strong number(s) stored in the list variable strong_num_list.
- Finally, we output the list of all potential string values.
From the input list of values, as shown above, we obtained an output list that contained the values 2, 145 and 1. The result is precise. Let's run the program once more with a new set of parameters.
Example 3:
# Factorial Computation
def factorial1(Number):
if(Number == 0 or Number == 1):
fact = 1
else:
fact = Number * factorial1(N - 1)
return fact
# Check for strong number
def strong_number(list):
n_list =[]
for i in list:
temp_N = i
sum = 0
while(temp_N):
r = temp_N % 10
sum += factorial1(r)
temp_N = temp_N // 10
if(sum == i):
n_list.append(i)
else:
pass
return n_list
# Input
a = [67, 87, 13, 949, 71, 890, 1018, 73, 1, 0]
strong_num_list = strong_number(a)
print(strong_num_list)
Output:

As seen above, a list with the values 1 and 0 as output has been returned. Consequently, the values on the list are strong numbers.
- Now, lets pass a different list of values to the above written code.
input_vals = [67, 87, 13, 949, 71, 890, 1018, 73, 11, 90]
Output Obtained

The output has been returned as a blank list, as seen above. As a result, none of the values in the list are considered to be strong numbers.
Strong Number with for Loop in Python
Example:
sum = 0
number=int(input("enter a number:"))
temp = number
while(temp > 0):
fact = 1
rem = temp % 10
for i in range(1, rem + 1):
fact = fact * i
print("Factorial of %d = %d " %(rem, fact))
sum = sum +fact
temp = temp // 10
print("Sum of factorials of the number %d = %d " %(number,sum))
if(sum == number):
print("Strong Number")
else:
print("Not a strong number")
Output:

Strong Number Python Program Employing Function
To find the strong number, we employ a built-in Python function.
Example:
import math
number = int(input("Enter Number: "))
sum = 0
temp = number
while(temp>0):
remainder = temp % 10
fact = math.factorial(remainder)
print("Factorial of %d = %d" %(remainder, fact))
sum = sum + fact
temp = temp // 10
print("Sum of factorials of a number %d = %d" %(number,sum))
if(sum == number):
print("Strong number")
else:
print("not a strong number")
Output

We have imported math since we are using a built-in function named factorial() found in the math library. The factorial of a single digit was calculated using this factorial() alone. As a result, it saves us from having to repeatedly calculate the factorial of each digit.
Conclusion
An idea in mathematics known as a strong number has several uses. Strong numbers are particular numbers where the sum of all digit factorials equals the sum itself. Python's numerous features enable us to swiftly and efficiently construct reliable number-checking applications.