Java Math negateExact() Method

The negateExact() method of Math class returns the negation for the specified argument, throwing an exception if the result overflows an int or a long.

Syntax:

1. public static int negateExact (int a)
2. public static long negateExact (long a)

Parameters:

The parameter ‘a’ represents the value to negate.

Return Value:

The negateExact () method returns the negation of a.

Throws:

The negateExact () method throws:

ArithmeticException- if the result overflows an int or long.

Example 1:

public class JavaMathNegateExactExample1 {
    public static void main(String[] args) {
        int a = 34;
        //returns the negation for a
        System.out.println("Negation of "+a+" is : "+Math.negateExact(a));
    }
}

Output:

Negation of 34 is : -34

Example 2:

public class JavaMathNegateExactExample2 {
    public static void main(String[] args) {
        long a = -8765;
        //returns positive value for negative a
        System.out.println("Negation of "+a+" is : "+Math.negateExact(a));
    }
}

Output:

Negation of -8765 is : 8765

Example 3:

public class JavaMathNegateExactExample3 {
    public static void main(String[] args) {
        Long a = 566l/0l;
        //throws exception if a is divided by zero
        System.out.println("Negation of "+a+" is : "+Math.negateExact(a));
    }
}

Output:

Exception in thread "main" java.lang.ArithmeticException: / by zero
         at com.TutorialAndExamples.JavaMathNegateExactExample3.main(JavaMathNegateExactExample
3.java:5)

Example 4:

public class JavaMathNegateExactExample4 {
    public static void main(String[] args) {
        Long a = Long.MIN_VALUE;
        //throws wxception if a is divided by zero
        System.out.println("Negation of "+a+" is : "+Math.negateExact(a));
    }
}

Output:

Exception in thread "main" java.lang.ArithmeticException: long overflow
         at java.lang.Math.negateExact(Math.java:994)
         at com.TutorialAndExamples.JavaMathNegateExactExample4.main(JavaMathNegateExactExample
4.java:7)