Python Set intersection_update() method
Python Set intersection_update() method
The set.intersection_update() method in Python removes the items that is not present in both sets.
It is different from the set.intersection() method, because the intersection()method returns a new set, with only the common elements whereas the intersection_update() method removes the unwanted items from the original set.
Syntax
set.intersection_update(set1, set2 ... etc)
Parameter
set1- This parameter represents the set to search for equal items
set2(optional)- This argument signifies the other set to search for equal items. One can compare as many sets as needed, only need to separate the sets with a comma.
Return
None
Example 1
# Python program explaining
# the intersection_update() method
#initializing set1
set1 = {"mango", "banana", "apple","tomato"}
print("Set 1:",set1)
# initializing set2
set2 = {"potato", "spinach","Carrot", "apple"}
print("Set 2:",set2)
# Removing the items that is not present in both sets.
set1.intersection_update(set2)
print("After intersection_update() method...")
print("Updated Set 1:",set1)
Output
Set 1: {'tomato', 'apple', 'mango', 'banana'}
Set 2: {'apple', 'Carrot', 'potato', 'spinach'}
After intersection_update() method...
Updated Set 1: {'apple'}
Example 2
# Python program explaining
# the intersection_update() method
# initializing set1
set1 = {"a", "b", "c","q","R"}
print("Set 1:",set1)
# initializing set2
set2 = {"a", "z", "e","q","R"}
print("Set 2:",set2)
# initializing set3
set3 = {"a", "g", "m","q","R"}
print("Set 3:",set3)
# removing the items that is not present in three of the sets. .
set1.intersection_update(set2, set3)
# printing the result
print("Updated Set 1:",set1)
Output
Set 1: {'R', 'a', 'b', 'q', 'c'}
Set 2: {'R', 'z', 'a', 'q', 'e'}
Set 3: {'R', 'a', 'm', 'q', 'g'}
Updated Set 1: {'R', 'a', 'q'}
Example 3
# Python program explaining
# the intersection_update() method
# initializing first set
A = {"a", "e", "i"}
# initializing second set
B = {"o", "u","a"}
# initializing third set
C = {"u", "z", "a","m"}
# initializing fourth set
D = {"f","h","l","h","m"}
# deleting the element that is not common between Set A and Set B
A.intersection_update(B,C,D)
# when no element is common
print("After the intersection_update() method...")
# printing set A
print("set A: ",A)
# printing set B
print("set B: ",B)
# printing set C
print("set C: ",C)
# printing set D
print("set D: ",D)
Output
After the intersection_update() method...
set A: set()
set B: {'o', 'a', 'u'}
set C: {'a', 'm', 'z', 'u'}
set D: {'l', 'm', 'h', 'f'}