Java Math decrementExact() Method

The decrementExact() method of Math class returns the argument which is decremented by one, throwing an exception is the result overflows an int or long.

Syntax:

public static int decrementExact (int a)

Parameters:

The parameter ‘a’ represents the value to decrement.

Return Value:

The decrementExact () method returns the result after decrementing the value.

Throws:

The decrementExact () method throws:

ArithmeticException- if the result overflows an int or a long

Example 1:

public class JavaMathDecrementExactExample1 {
    public static void main(String[] args) {
        int a=90;
        //returns the result after decrementing the int value
        System.out.println("Decremented value : "+Math.decrementExact(a));
    }
}

Output:

Decremented value : 89

Example 2:

public class JavaMathDecrementExactExample2 {
    public static void main(String[] args) {
        //type cast the value Math.PI into int
        int a= (int) Math.PI;
        System.out.println("Cosine value for "+a+" = "+Math.decrementExact(a));
    }
}

Output:

Cosine value for 3 = 2

Example 3:

public class JavaMathDecrementExactExample3 {
    public static void main(String[] args) {
        //returns the result after decrementing the long value
        long x = Long.MAX_VALUE;
        System.out.println("Decremented value for "+x+":
"+Math.decrementExact(x));
    }
}

Output:

Decremented value for 9223372036854775807: 9223372036854775806

Example 4:

public class JavaMathDecrementExactExample4 {
    public static void main(String[] args) {
        //returns an exception is the result overflows a long
long x = Long.MIN_VALUE;
        System.out.println("Decremented value for "+x+":
"+Math.decrementExact(x));
    }
}

Output:

Exception in thread "main" java.lang.ArithmeticException: long overflow
            at java.lang.Math.decrementExact(Math.java:960)
            at com.Tutorials And
Examples.JavaMathDecrementExactExample4.main
(JavaMathDecrementExactExample4.java:7)