Java Math log10() Method
The log10() method of Math class returns the base 10 logarithmic value for the specified double argument.
Syntax:
public static double log10(double a)
Parameters:
The parameter ‘a’ represents a double value.
Return Value:
The log10() method returns the base 10 logarithm of a.
Special cases of the log10() method are as follows:
- It returns NaN, if the argument is NaN or less than zero.
- It returns positive infinity, if the argument passed is positive infinite.
- It returns negative infinity, if the argument passed is positive zero or negative zero.
- It returns n, if the argument is equal to 10n for integer n.
Example 1:
public class JavaMathLog10Example1 {
public static void main(String[] args) {
double a = 10;
//returns the natural base 10 logarithm of a
System.out.println("Logrithm10 value : "+Math.log10(a));
}
}
Output:
Logrithm10 value : 1.0
Example 2:
public class JavaMathLog10Example2 {
public static void main(String[] args) {
double a = -98;
//returns NaN, if the argument is NaN or less than zero
System.out.println("Logrithm10 value for "+a +" : "+Math.log10(a));
}
}
Output:
Logrithm10 value for -98.0 : NaN
Example 3:
public class JavaMathLog10Example3 {
public static void main(String[] args) {
double a = 98/0.0d;
//returns positive infinity, if the argument passed is positive infinite
System.out.println("Logrithm10 value for "+a +" : "+Math.log10(a));
}
}
Output:
Logrithm10 value for Infinity : Infinity
Example 4:
public class JavaMathLog10Example4 {
public static void main(String[] args) {
double a = 0;
//returns negative infinity, if the argument passed is positive or negative zero
System.out.println("Logrithm10 value for "+a +" : "+Math.log10(a));
}
}
Output:
Logrithm10 value for 0.0 : -Infinity
Example 5:
public class JavaMathLog10Example5 {
public static void main(String[] args) {
double a = 100000000;
//returns n, if the argument is equal to 10n for integer n
System.out.println("Logrithm10 value for "+a +" : "+Math.log10(a));
}
}
Output:
Logrithm10 value for 1.0E8 : 8.0